Sony LG10 Bedienungsanleitung Seite 31

Examples of setting linear compensation amounts.
As the mechanical error is measured, set the compensation amount with reference to the
following examples.
L:
s:
When L>s, add a compensation amount to the displayed value.
Set an appropriate positive compensation amount.
• Example in millimeter operation
• Example in inch operation
When L < s, subtract a compensation amount from the displayed value.
Set an appropriate negative compensation amount.
• Example in millimeter operation
• Example in inch operation
Addition or subtraction to or from the displayed value for the displacement
Length of block gauge a
Displayed value for the distance between the surfaces A and C
Where L = 250 mm, s = 249.9960 mm, the difference between L and s is 0.004 mm. The amount
χ to be compensated per meter (1000 mm) is:
χ
0.004mm
/
250 mm 1000 mm
The compensation amount, therefore, is 0.016 mm.
Set "015" as the closest compensation amount.
Where L = 9.84252" and s=9.84236", the difference between L and s is 0.00016". The amount
χ to be compensated per inch is:
χ
0.00016"
/
9.84252" 1"
The compensation amount, therefore, is 0.000016". Set "015" as the closest compensation
amount.
Where L=250 mm, s=250.0040 mm, the difference between L and s is 0.004 mm. The amount
χ to be compensated per meter (1000 mm) is:
χ
0.004 mm
/
250 mm 1000 mm
Therefore the compensation amount is –0.016 mm.
Set "–015" as the closest compensation amount.
Where L=9.84252" and s=9.84268", the difference between L and s is 0.00016". The amount χ
to be compensated per inch is:
χ
0.00016"
/
9.84252" 1"
The compensation amount, therefore, is –0.000040".
Set "–015" as the closest compensation amount.
χ = 0.016 mm
χ = 0.000016"
χ = 0.016 mm
χ = 0.000016"
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